SQL Queries
select * from employees;
select first_name,last_name
from employees
where last_name like '%a';
select count(last_name) as count_last_name,gender
from employees
where last_name like '%a'
group by gender;
select count(last_name) as count_last_name,gender
from employees
where last_name like 'ja%'
group by gender;
select count(last_name) as count_last_name,gender
from employees
where last_name like 'ja%i'
group by gender;
select count(distinct last_name) as count_last_name,gender
from employees
where last_name like 'ja%i'
group by gender;
select distinct last_name as unique_names
from employees
where last_name like 'ja%i';
Comments
Post a Comment